Khi thực hiện phép tính \(\dfrac{x^2+2x}{6x^2-12x+6}:\dfrac{x+2}{4x-4}\), ta có kết quả là
\(\dfrac{2x}{3\left(x-1\right)}\).\(-\dfrac{2x}{3\left(x-1\right)}\).\(\dfrac{2x}{3}\).\(\dfrac{2x\left(x+2\right)}{3\left(x-2\right)}\).Hướng dẫn giải:\(\dfrac{x^2+2x}{6x^2-12x+6}:\dfrac{x+2}{4x-4}\)
\(=\dfrac{x\left(x+2\right)}{6\left(x-1\right)^2}.\dfrac{4\left(x-1\right)}{x+2}\)
\(=\dfrac{2x}{3\left(x-1\right)}\).