Sau khi thực hiện phép tính \(\dfrac{x^3-27}{8x+16}.\dfrac{x^2-4}{x^2+3x+9}\), ta có kết quả là
\(\dfrac{\left(x-3\right)\left(x-2\right)}{8}\).\(\dfrac{\left(x-3\right)\left(x+2\right)}{8}\).\(\dfrac{x^2+3x+6}{8}\).\(\dfrac{\left(x+2\right)\left(x-2\right)}{8}\).Hướng dẫn giải:\(\dfrac{x^3-27}{8x+16}.\dfrac{x^2-4}{x^2+3x+9}\)
\(=\dfrac{\left(x-3\right)\left(x^2+3x+9\right).\left(x-2\right)\left(x+2\right)}{8\left(x+2\right)\left(x^2+3x+9\right)}\)
\(=\dfrac{\left(x-3\right)\left(x-2\right)}{8}\).