\(\lim\limits_{x\rightarrow1}\frac{x^3+x^2-2}{\sin\left(x-1\right)}\) bằng bao nhiêu?
\(1\) \(0\) \(5\) \(2\) Hướng dẫn giải:
\(\lim\limits_{x\rightarrow1}\dfrac{x^3+x^2-2}{\sin\left(x-1\right)}=\lim\limits_{x\rightarrow1}\dfrac{x^2+2x+2}{\dfrac{\sin\left(x-1\right)}{x-1}}=5\)