Ôn tập chương III
Các câu hỏi tương tự
2/2.3+2/3.4+2/4.5+...+2/x(x+1)=2008/2010
Xem chi tiết
Tính nhanh:
A = 2/3.4 + 2/4.5 + 2/5.6 +......+ 2/98.99.
B = -1/2.3.4 + -1/3.4.5 + -1/4.5.6 +.........+ -1/28.29.30.
Tính :
\(\dfrac{1.2+2.3+3.4+...+20.21}{1+2-3-4+5+6-7-8+...+197+198-199-200+201}\)
16 tháng 2 2023 lúc 20:33
1-\(\dfrac{1}{1.2}\)-\(\dfrac{1}{2.3}\)-...-\(\dfrac{1}{9.10}\)<\(\dfrac{1}{9}\)
Tìm x :
\(\dfrac{1}{1.2}.\left|2x-1\right|+\dfrac{1}{2.3}.\left|2x-1\right|+\dfrac{1}{3.4}+..+\dfrac{1}{1996.1997}.\left|2x-1\right|=1996\)
Tính nhanh
E = \(\dfrac{-9}{10}.\dfrac{5}{14}+\dfrac{1}{10}.\dfrac{-9}{2}+\dfrac{1}{7}.\dfrac{-9}{10}\)
Chứng tỏ rằng: \(\dfrac{1}{1.2}+\dfrac{1}{2.3}\text{+}\dfrac{1}{3.4}\text{+}.........\text{+}\dfrac{1}{99.100}\)< 1
Mau nha
Bài 1 : Thực hiện phép tính ( tính hợp lý nếu có thể )a ) dfrac{1}{12}+dfrac{3}{4}b ) dfrac{-4}{7}.1dfrac{1}{2}c )dfrac{7}{9}+left(dfrac{2}{3}+dfrac{-7}{9}right)d )dfrac{2}{3}-dfrac{1}{3}:dfrac{3}{4}e )dfrac{-7}{25}.dfrac{11}{13}+dfrac{-7}{25}.dfrac{2}{13}g )2dfrac{2}{5}.0,25-left(dfrac{11}{20}+75%right):dfrac{13}{5}
Đọc tiếp
Bài 1 : Thực hiện phép tính ( tính hợp lý nếu có thể )
a ) \(\dfrac{1}{12}+\dfrac{3}{4}\)
b ) \(\dfrac{-4}{7}.1\dfrac{1}{2}\)
c )\(\dfrac{7}{9}+\left(\dfrac{2}{3}+\dfrac{-7}{9}\right)\)
d )\(\dfrac{2}{3}-\dfrac{1}{3}:\dfrac{3}{4}\)
e )\(\dfrac{-7}{25}.\dfrac{11}{13}+\dfrac{-7}{25}.\dfrac{2}{13}\)
g )\(2\dfrac{2}{5}.0,25-\left(\dfrac{11}{20}+75\%\right):\dfrac{13}{5}\)
a) dfrac{2}{1^2}.dfrac{6}{2^2}.dfrac{12}{3^2}.dfrac{20}{4^2}.dfrac{30}{5^2}.....dfrac{110}{10^2}.x-20
b) left(1+dfrac{1}{2}+dfrac{1}{3}+...+dfrac{1}{2013}right).x+2013dfrac{2014}{1}+dfrac{2015}{2}+...+dfrac{4025}{2012}+dfrac{4026}{2013}
c) left(dfrac{1}{1.2}+dfrac{1}{3.4}+...+dfrac{1}{99.100}right).xdfrac{2012}{51}+dfrac{2012}{52}+...+dfrac{2012}{99}+dfrac{2012}{100}
Đọc tiếp
a) \(\dfrac{2}{1^2}.\dfrac{6}{2^2}.\dfrac{12}{3^2}.\dfrac{20}{4^2}.\dfrac{30}{5^2}.....\dfrac{110}{10^2}.x=-20\)
b) \(\left(1+\dfrac{1}{2}+\dfrac{1}{3}+...+\dfrac{1}{2013}\right).x+2013=\dfrac{2014}{1}+\dfrac{2015}{2}+...+\dfrac{4025}{2012}+\dfrac{4026}{2013}\)
c) \(\left(\dfrac{1}{1.2}+\dfrac{1}{3.4}+...+\dfrac{1}{99.100}\right).x=\dfrac{2012}{51}+\dfrac{2012}{52}+...+\dfrac{2012}{99}+\dfrac{2012}{100}\)
tính:
A=1.98+2.97+3.96+...+98.1/1.2+2.3+3.4+...+98.99