Question

(3x-1).( -1/2x +5)=0

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Answer 1

⇔\(\left\{{}\begin{matrix}3x-1=0\\\frac{-1}{2}\end{matrix}\right.x+5=0\)

⇔\(\left\{{}\begin{matrix}3x=1\\\frac{-1}{2}\end{matrix}\right.x=-5\)

⇔\(\left\{{}\begin{matrix}x=\frac{1}{3}\\x=10\end{matrix}\right.\)

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Answer 2

do (3x-1).( -1/2x +5)=0

=>\(\left[{}\begin{matrix}3x-1=0\\\frac{-1}{2}x+5=0\end{matrix}\right.=>\left[{}\begin{matrix}3x=1\\\frac{-1}{2}x=-5\end{matrix}\right.=>\left[{}\begin{matrix}x=\frac{1}{3}\\x=-5:\frac{-1}{2}\end{matrix}\right.=>\left[{}\begin{matrix}x=\frac{1}{3}\\x=10\end{matrix}\right.\)(T/M)