Ta có:
\(\left\{{}\begin{matrix}n_{SO2}=\frac{6,4}{32}=0,2\left(mol\right)\\n_{NaOH}=0,5.0,6=0,3\left(mol\right)\end{matrix}\right.\)
Xét tỉ số : \(T=\frac{n_{NaOH}}{n_{SO2}}=\frac{0,3}{0,2}=1,5\)
Vì 1< T < 2 => Phản ứng tạo cả 2 muối.
\(2NaOH+SO_2\rightarrow Na_2SO_3+H_2O\)
2x_______________x____________x
\(NaOH+SO_2\rightarrow NaHSO_3\)
y_________y___________y
Gọi \(\left\{{}\begin{matrix}n_{Na2SO3}:x\left(mol\right)\\n_{NaHSO3}:y\left(mol\right)\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}2x+y=0,3\\x+y=0,2\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=0,1\\y=0,1\end{matrix}\right.\)
\(\left\{{}\begin{matrix}CM_{Na2SO3}=\frac{0,1}{0,5}=0,2M\\CM_{NaHSO3}=\frac{0,1}{0,5}=0,2M\end{matrix}\right.\)
