Question

Giải phương trình

32-4(0,5y-5)=3y-19

Answer 1

\(32-4\left(0,5y-5\right)=3y-19\Leftrightarrow32-2y+20=3y-19\Leftrightarrow3y+2y=32+20+19\Leftrightarrow5y=71\Leftrightarrow y=\frac{71}{5}=14,2\)

Answer 2

Ta có: 32-4(0,5y-5)=3y-19

⇔32-2y+20-3y+19=0

⇔71-5y=0

⇔5y=71

hay \(y=\frac{71}{5}\)

Vậy: \(y=\frac{71}{5}\)