\(x+\frac{2}{3}=2\frac{1}{2}\)
\(x+\frac{2}{3}=\frac{5}{2}\)
\(x=\frac{5}{2}-\frac{2}{3}\)
\(x=\frac{11}{6}\)
\(8,75.x+1,25.x=26,3\)
\(x.\left(8,75+1,25\right)=26,3\)
\(x.10=26,3\)
\(x=26,3\div10\)
\(x=2,63\)
\(x-4\frac{5}{6}=2\frac{1}{6}+\frac{5}{6}\)
\(x-\frac{29}{6}=3\)
\(x=\frac{47}{6}\)
\(5\frac{4}{5}+x-7\frac{7}{18}=15\frac{3}{4}\)
\(\frac{29}{5}+x-\frac{133}{18}=\frac{63}{4}\)
\(\frac{29}{5}+x=\frac{63}{4}+\frac{133}{18}\)
\(\frac{29}{5}+x=\frac{259}{8}\)
\(x=\frac{259}{8}-\frac{29}{5}\)
\(x=\frac{1063}{40}\)
X - \(4\frac{5}{6}\)= \(2\frac{1}{6}\)+ \(\frac{5}{6}\)
X - \(\frac{29}{6}\)= \(\frac{13}{6}\)+ \(\frac{5}{6}\)
X = \(\frac{13}{6}+\frac{5}{6}+\frac{29}{6}\)
X =\(\frac{47}{6}\)
Ủng hộ nha! :)
\(x-\frac{29}{6}=\frac{13}{6}+\frac{5}{6}\)
\(x-\frac{29}{6}=3\)
\(x=3+\frac{29}{6}=\frac{47}{6}\)
\(X+\frac{2}{3}=\frac{5}{2}\)
\(X=\frac{5}{2}-\frac{2}{3}\)
X = 11/6
X x ( 8,75 +1,25 ) = 26,3
X x 10 = 26 ,3
X = 26,3 : 10
X = 2,63
\(\frac{29}{5}+x-\frac{133}{18}=\frac{63}{4}\)
\(\frac{29}{5}+x=\frac{63}{4}+\frac{133}{18}=\frac{833}{36}\)
\(x=\frac{833}{36}-\frac{29}{5}=\frac{3121}{180}\)