a) 4Al+3O2−−>2Al2O34Al+3O2−−>2Al2O3
nAl=5,427=0,2(mol)nAl=5,427=0,2(mol)
nO2=34nAl=0,15(mol)nO2=34nAl=0,15(mol)
VO2=0,15.22,4=3,36(l)VO2=0,15.22,4=3,36(l)
b) Vkk=5VO2=3,36.5=16,8(l)Vkk=5VO2=3,36.5=16,8(l)
c) 2KClO3−−>2KCl+3O22KClO3−−>2KCl+3O2
nKClO3=23nO2=0,1(mol)nKClO3=23nO2=0,1(mol)
mKClO3=0,1.122,5=12,25(g)
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Ta có:
\(n_{Al}=\frac{5,4}{27}=0,2\left(mol\right)\)
\(4Al+3O_2\rightarrow2Al_2O_3\)
Theo PTHH:
\(\Rightarrow n_{O2}=\frac{3}{4}n_{Al}=0,15\left(mol\right)\)
\(\Rightarrow V_{O2}=0,15.22,4=3,36\left(l\right)\)
\(\Rightarrow V_{kk}=V_{O2}.5=3,36.5=16,8\left(l\right)\)
\(PTHH:2KClO_3\rightarrow2KCl+3O_2\)
\(n_{KClO3}=0,1\left(mol\right)\Rightarrow m_{KClO3}=0,1.122,5=12,25\left(g\right)\)
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