x^2-x-1=0
\(\Leftrightarrow\left[{}\begin{matrix}x=\frac{1+\sqrt{5}}{2}\\x=\frac{1-\sqrt{5}}{2}\end{matrix}\right.\)
Vậy..........
x^2-x-1=0
\(\Leftrightarrow\left[{}\begin{matrix}x=\frac{1+\sqrt{5}}{2}\\x=\frac{1-\sqrt{5}}{2}\end{matrix}\right.\)
Vậy..........
1. (4x-10).(24+5x)=0
2 .(2x-5).(3x-2)=0
3. (2x-1).(3x+1)=0
4. x.(\(x\)2-1)=0
5.(5x+3).(\(x^2\)+4).(x-1)=0
6.(x-1).(x+2).(x+3)=0
7.(x-1).(x+5).(-3x+8)=0
Tìm x biêt :
a. ( x + 3)2 + ( x - 2).( x + 2) - 2. ( x - 1)2 = 7
b. 36x2 - 4g = 0
c. ( x + 3) . ( x2 - 3x + g) - x . ( x - 1 ) . ( x + 1) - 27 = 0
d. x2 - 4x + 3 = 0
e. x . ( 2x -1 ) - ( x- 2) . ( 2x + 3) = 0
g. ( x - 1 ) . ( x + 2) - x - 2 = 0
mong jup dỡ ạ
Tìm x:
a) 2x (x-5) -(x2-10x +25)=0
b) x2 - 9 +3x(x+3) = 0
c) x3 - 16x = 0
d) (2x+3)(x-2) - (x2 -4x+4) = 0
e) 9x2 -(x2 -2x +1)=0
f)x3-4x2 -9x +36 = 0
g) 3x - 6 = (x-1).(x-2)
i) (x-2).(x+2) +(2x+1)2 =-5x.(x-3) =5
k) x2 -1 = (x-1).(2x+3)
l) (2x-1)2 +(x+3).(x-3) -5x(x-2)=6
Câu 1. Giải các phườn trình sau:
a, 3x+6=0
b, 2x-10=0
c, 3x-7=11
d, 3x-9=0
e, 3x(2-x) =15(x-2)
f, (x+5)(x+4)=0
g, x(x+4)=0
h, (2x -4)(x-2)=0
i, (x+1/5)(2x-3)=0
k, x²-4x=0
m, 4x²-1=0
n, x²-6x+9=0
l, (3x-5)²-(x+4)²=0
o, 7x(x+2)-5(x+2)=0
p, 3x(2x-5)-4x+10=0
q, (2-2x)-x²+1=0
r, x(1-3x)=5(1-3x)
s, 2x-3/4+x+1/6=3
t, x-3/4-2x+1/3=x/6
u, x+1/13+x+2/12=x+3/11+x+4/10
v, 2x+1/15+2x+2/14=2x+3/13+2x+4/12
Giúp e nha mn. E cảm ơn trc ạ!
Tìm x, biết:
1) 2x (x-3) + 5x - 15 = 0
2) x ( 2x - 7) - 4x + 14 = 0
3) x2 - 12x + 36 = 0
4) (x + 3) (x2 - 3x + 9) - x (x -1)(x + 1) -27 = 0
TÌm x:
( x + 2)4 + (x -4) 4 = 162
x2 - 5x - 21 = 0
x2 - (x+1)2 = 0
(x - 1).(x+2) - x-2= 0
x2 - 4x +3 = 0
3x ( x-4) +12x - 48 = 0
(2x-1).(5-3x) = (x+2).(5-3x)
a,(x+3)^2+(x-2).(x+2)-2(x-1)^2=7
b,(x+2)^2-(x-2)(x+2)=0
c,(3x-2)^2-(2x-1)^2=0
d,x^2-4x+3=0
mọi người à, có thể làm giúp tớ mấy câu hỏi tìm x này không? cảm ơn rất nhiều ≥√≤
a, |x| + |x-1| = 0
b, |x| + |x-1| = 1
c, |x| + |x-1| = 1/2 d, |x| + |x-1| = 5 e, |x| + |x^3| = 0 f, |x-1| + |x^2 - 1| = 0 g, x^2 + |x| = 0 h, (x-1)^2 + |x^2 - 1| = 0 cảm ơn cậu một lần nữa nhé, vì đã giúp mình làm bài này <3Tìm x:
a) (x-2)^3-5(x-1)(x-2)+x(5-x)(x+5)=0
b) (4x+1)(16x^2-4x+1)-8x^2(x-1)=0
1) tim x
A) x2-25-(x+5)=0
B) ( 2x-1)2-(4x2-1)=0
C) x2(x2+4)-x2-4=0