Ta có \(\left(x-4\right)^2-36=0\)
\(\Leftrightarrow\left(x-4\right)^2-6^2=0\)
\(\Leftrightarrow\left(x-4-6\right)\left(x-4+6\right)=0\)
\(\Leftrightarrow\left(x-10\right)\left(x+2\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=10\\x=-2\end{matrix}\right.\)
Vậy \(x\in\left\{10;-2\right\}\)
\(\left(x-4\right)^2-6^2=0\)
\(\Leftrightarrow\left(x-4-6\right)\left(x-4+6\right)=0\)
\(\Leftrightarrow\left(x-10\right)\left(x+2\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=10\\x=-2\end{matrix}\right.\)
Vậy ...
