Bài làm
\(\frac{3\left(3-x\right)}{8}+\frac{2\left(5-x\right)}{3}=1-\frac{x}{2}-2\)
\(\Leftrightarrow\frac{9\left(3-x\right)}{24}+\frac{16\left(5-x\right)}{24}=\frac{24}{24}-\frac{12x}{24}-\frac{48}{24}\)
\(\Rightarrow27-9x+80-16x=24-12x-48\)
\(\Leftrightarrow-13x=-131\)
\(\Leftrightarrow x=\frac{131}{13}\)
Vậy....
Ta có : \(\frac{3\left(3-x\right)}{8}+\frac{2\left(5-x\right)}{3}=\frac{1-x}{2}-2\)
=> \(\frac{9\left(3-x\right)}{24}+\frac{16\left(5-x\right)}{24}=\frac{12\left(1-x\right)}{24}-\frac{24}{12}\)
=> \(9\left(3-x\right)+16\left(5-x\right)=12\left(1-x\right)-24\)
=> \(27-9x+80-16x=12-12x-24\)
=> \(27-9x+80-16x-12+12x+24=0\)
=> \(-13x=-119\)
=> \(x=\frac{119}{13}\)
Vậy phương trình trên có tập nghiệm là \(S=\left\{\frac{119}{13}\right\}\)
