\(\Leftrightarrow\left(x-1\right)^2=-3.-27\)
\(\Leftrightarrow\left(x-1\right)^2=81\)
\(\Leftrightarrow\left[{}\begin{matrix}x-1=9\\x-1=-9\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=10\\x=-8\end{matrix}\right.\)
\(\frac{-3}{x-1}=\frac{x-1}{-27}\)
=> \(\frac{81}{-27.\left(x-1\right)}=\frac{\left(x-1\right)^2}{-27.\left(x-1\right)}\)
=> \(81=\left(x-1\right)^2\)
=> \(x-1=9\) hoặc x - 1 = -9
=> x = 9 + 1 = 10 x = -9 + 1 = - 8
\(\frac{-3}{x-1}\)=\(\frac{x-1}{-27}\)
➜(x-1)(x-1)=-3(-27) (Nhân chéo nha!!!)
➜\(\left(x-1\right)^2\)=81
➜\(\left(x-1\right)^2\)=\(9^2\)
➜\(\left[{}\begin{matrix}x-1=9\\x-1=-9\end{matrix}\right.\)
➜\(\left[{}\begin{matrix}x=10\\x=-8\end{matrix}\right.\)
Vậy S=\(\left\{10;-8\right\}\)
Thôi bớt dành bài đi mấy 3!!....
\(\frac{-3}{x-1}=\frac{x-1}{-27}\)
\(\Leftrightarrow81=\left(x-1\right)^2\)
\(\Leftrightarrow9^2=\left(x-1\right)^2\)
\(\Leftrightarrow\left[{}\begin{matrix}x-1=9\\x-1=-9\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=10\\x=-8\end{matrix}\right.\)
