\(x-\frac{3}{7}-\frac{1}{3}=2x+\frac{1}{3}\)
\(x-\frac{16}{21}=2x+\frac{1}{3}\)
\(x-\frac{16}{21}-2x-\frac{1}{3}=0\)
\(-x-\frac{23}{21}=0\)
\(-x=\frac{23}{21}\)
\(x=-\frac{23}{21}\)
\(x-\frac{3}{7}-\frac{1}{3}=2x+\frac{1}{3}\)
\(\Leftrightarrow x-\frac{3}{7}-\frac{1}{3}-2x-\frac{1}{3}=0\)
\(\Leftrightarrow-x-\frac{23}{21}=0\)
\(\Leftrightarrow x=-\frac{23}{21}\)
Vậy \(S=\left\{-\frac{23}{21}\right\}\)
Ta có: \(\frac{x-3}{7}-\frac{1}{3}=\frac{2x+1}{3}\)
\(\Leftrightarrow\frac{x-3}{7}-\frac{1}{3}-\frac{2x+1}{3}=0\)
\(\Leftrightarrow\frac{x-3}{7}-\left(\frac{1}{3}+\frac{2x+1}{3}\right)=0\)
\(\Leftrightarrow\frac{x-3}{7}-\left(\frac{1+2x+1}{3}\right)=0\)
\(\Leftrightarrow\frac{x-3}{7}-\frac{2x+2}{3}=0\)
\(\Leftrightarrow\frac{3\left(x-3\right)}{21}-\frac{7\left(2x+2\right)}{21}=0\)
\(\Leftrightarrow3x-9-14x-14=0\)
\(\Leftrightarrow-23-11x=0\)
\(\Leftrightarrow11x=-23\)
hay \(x=\frac{-23}{11}\)
Vậy: \(x=\frac{-23}{11}\)
x - \(\frac{3}{7}\) - \(\frac{1}{3}\) = 2x + \(\frac{1}{3}\)
\(\Leftrightarrow\) x - \(\frac{16}{21}\) = 2x + \(\frac{1}{3}\)
\(\Leftrightarrow\) x - 2x = \(\frac{1}{3}\) + \(\frac{16}{21}\)
\(\Leftrightarrow\) -x = \(\frac{23}{21}\)
\(\Leftrightarrow\) x = \(\frac{-23}{21}\)
Vậy S = {\(\frac{-23}{21}\)}
Chúc bạn học tốt!