\(\left|2x-1\right|=\left|x+2\right|\)
\(\Rightarrow\left|2x-1\right|=x+2.\)
\(\Rightarrow\left[{}\begin{matrix}2x-1=x+2\\2x-1=-x-2\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}2x-x=2+1\\2x+x=-2+1\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}1x=3\\3x=-1\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=3:1\\x=\left(-1\right):3\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=3\\x=-\frac{1}{3}\end{matrix}\right.\)
Vậy \(x\in\left\{3;-\frac{1}{3}\right\}.\)
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\(\left|2x-1\right|=\left|x+2\right|\)
\(\left[{}\begin{matrix}2x-1=x+2\\2x-1=-x-2\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\3x=-1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-\frac{1}{3}\end{matrix}\right.\)