\(\frac{x-1}{x+5}=\frac{6}{7}\) \(\Rightarrow7\left(x-1\right)=6\left(x+5\right)\)
\(\Rightarrow7x-7=6x+30\)
\(\Rightarrow7x-6x=7+30\) \(\Rightarrow x=37\)
Vậy \(x=37\)
Ta có: \(\frac{x-1}{x+5}=\frac{6}{7}\)
\(\Leftrightarrow\left(x-1\right)\cdot7=6\left(x+5\right)\)
\(\Leftrightarrow7x-7=6x+30\)
\(\Leftrightarrow7x-7-6x-30=0\)
\(\Leftrightarrow x-37=0\)
hay x=37
Vậy: x=37