Lời giải:
\(x=\frac{2-\sqrt{3}}{2}=\frac{4-2\sqrt{3}}{4}=\frac{3+1-2\sqrt{3}}{4}=\frac{(\sqrt{3}-1)^2}{2^2}\)
\(\Rightarrow \sqrt{x}=\frac{\sqrt{3}-1}{2}\Rightarrow 1-\sqrt{x}=\frac{3-\sqrt{3}}{2}\)
\(\Rightarrow P=\frac{1}{(1-\sqrt{x})^3}=\frac{8}{(3-\sqrt{3})^3}\)