Ta có: (x - 1)(2x + 1) + 2x = 2
<=> (x - 1)(2x + 1) + 2x - 2 = 0
<=> (x - 1)(2x + 1) + 2(x - 1) = 0
<=> (x - 1)(2x + 1 + 2) = 0
<=> (x - 1)(2x + 3) = 0
<=> \(\left[{}\begin{matrix}x-1=0\\2x+3=0\end{matrix}\right.\)
<=> \(\left[{}\begin{matrix}x=1\\x=-\frac{3}{2}\end{matrix}\right.\)
a) (2x+1)^2-2x-1=2b) (x^2-3x)^2+5(x^2-3x)+6=0c) (x^2-x-1)(x^2-x)-2=0d) (5-2x)^2+4x-10=8e) (x^2+2x+3)(x^2+2x+1)=3f) x(x-1)(x^2-x+1)-6=0
Bài 1: giải các pt sau:
1,(x-1)^2-(x+1)^2=2(x+3)
2,(2x-1)^2-(2x+1)^2=4(x-3)
3,(2x+3)^2-(2x+3).(2x-4)=-(x-2)^2
4,8x^3-(x+1)^3=3x-3
5,(3x-2).(9x^2+6x+4)-(3x+1).(9x^2-3x+1)=(2x+1).(2x-1)-4x(x-3)
\(\dfrac{2}{x+\dfrac{1}{1+\dfrac{x+1}{x+2}}}\)
\(\dfrac{x^2+2x+1}{x^2+2x+2}+\dfrac{x^2+2x+2}{x^2+2x-6}=\dfrac{7}{6}\)
Bài 1: Giải các phương trình tích sau:
2. a) (3x + 2)(x2 –1) = (9x2 – 4)(x + 1) b)x(x + 3)(x – 3) – (x + 2)(x2 – 2x + 4) = 0
c) 2x(x – 3) + 5(x – 3) = 0 d) (3x – 1)(x2 + 2) = (3x – 1)(7x – 10)
e) (x + 2)(3 – 4x) = x2 + 4x + 4 f) x(2x – 7) – 4x + 14 = 0
g) 3x – 15 = 2x(x – 5) h) (2x + 1)(3x – 2) = (5x – 8)(2x + 1)
i) 0,5x(x – 3) = (x – 3)(1,5x – 1) j) (2x2 + 1)(4x – 3) = (x – 12)(2x2 + 1)
k) x(2x – 9) = 3x(x – 5) l) (x – 1)(5x + 3) = (3x – 8)(x – 1)
(x - 1)/(x + 2) * (2x - 1)/(2x + 1) = 8/(4x ^ 2 - 1)
Giải pt
a) 2x(x+5) -(x-3) ²=x²+6
b) 6(x-3) +(x-1) ²-(x+1) ²=2x
c) 2x-3(x-2) =x+6+(x+1)
d) (x+4) ²-(x+8) (x-8) =96
e) 5x-2/6+3-4x/2=2-x+7/3
f) 2x-1/2=2x+1/4-1-2x/8
Tìm x, biết
a)3x³-27x=0
b) 2x³-12x²+18x=0
(x-2)(2x-1) = 2x2 - 3(1-2x)
Bài 1. Giải các phương trình sau bằng cách đưa về dạng ax + b = 0:
1a) 1,2 – (x – 0,8) = –2(0,9 + x) b) 3,6 – 0,5(2x + 1) = x – 0,25(2 – 4x)
c) 2,3x – 2(0,7 + 2x) = 3,6 – 1,7x d) 0,1 – 2(0,5t – 0,1) = 2(t – 2,5) – 0,7
e) 3 + 2,25x +2,6 = 2x + 5 + 0,4x f) 5x + 3,48 – 2,35x = 5,38 – 2,9x + 10,42
2
a) 5 – (x – 6) = 4(3 – 2x) b) 2x(x + 2)2 – 8x2 = 2(x – 2)(x2 + 2x + 4)
c) 7 – (2x + 4) = – (x + 4) d) (x – 2)3 + (3x – 1)(3x + 1) = (x + 1)3
e) (x + 1)(2x – 3) = (2x – 1)(x + 5) f) (x – 1)3 – x(x + 1)2 = 5x(2 – x) – 11(x + 2)
g) (x – 1) – (2x – 1) = 9 – x h) (x – 3)(x + 4) – 2(3x – 2) = (x – 4)2
i) x(x + 3)2 – 3x = (x + 2)3 + 1 j) (x + 1)(x2 – x + 1) – 2x = x(x + 1)(x – 1)
giải phương trình tícha, 3x-1=0 b, 5x-2=x+4c, 2.(4-2x)-1 =x-3d, 2x-1/3 - x+2/6=3x e, (2x-1).(x.x-6)=0f, (x+2) .(5-4x)=x.x+4x+4
a. x (x²-1)=0
b. (x-1/2) 2x+5=0
c. x-2 (2/3x - 6)=0
d. x² - 2x=0
e.(x²-2x+1)-4=0
f.x(2x-1)=0
g.4x²+4x+1=0
h.x²-5x+6=0
i. 2x²+3x=0
