a) CaO+2HCl--->CaCl2+H2O
x-----------2x----------x
b) CuO+2HCl---->CuCl2+H2O
y----------2y
b) n HCl=0,4.0,1=0,04(mol)
Theo bài ta có hpt
\(\left\{{}\begin{matrix}56x+80y=1,36\\2x+2y=0,04\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=0,01\\y=0,01\end{matrix}\right.\)
%m CaO=0,01.56/1,36.100%=41,18%
%m CuO=100%-41,18=58,82%
c) m muối=0,01.111+0,01.135=2,46(g)
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