\(a^3-b^3-ac^2+bc^2=0\)
\(\Leftrightarrow\left(a-b\right)\left(a^2+ab+b^2\right)-c^2\left(a-b\right)=0\)
\(\Leftrightarrow\left(a-b\right)\left(a^2+ab+b^2-c^2\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}a-b=0\\a^2+b^2-c^2=-ab\end{matrix}\right.\)
TH1: \(a=b\Rightarrow\) chịu thua ko tính được góc C
TH2: \(a^2+b^2-c^2=-ab\Rightarrow cosC=\frac{a^2+b^2-c^2}{2ab}=-\frac{1}{2}\)
\(\Rightarrow C=120^0\)