\(Z+2HCl\rightarrow ZnCl_2+H_2\)
a ___________________ a
\(2Al+6HCl\rightarrow2AlCl_3+3H_2\)
b_______________________1,5b
\(Zn+Cl_2\rightarrow ZnCl_2\)
a____a___________
\(2Al+2Cl_2\rightarrow2AlCl_3\)
b____ 1,5b________
Gọi a là số mol Zn b là số mol Al
\(n_{H2}=\frac{8,96}{22,4}=0,4\left(mol\right)\)
Ta có
\(n_{CL2}=n_{H2}=0,4\left(mol\right)\)
\(\rightarrow V=0,4.22,4=8,96\left(l\right)\)