PTHH A+2HCL\(\rightarrow\)ACL2 +H2
nH2=\(\frac{4,48}{22,4}\)=0,2(MOL)
Theo pt nA=nH2=0,2(MOL)
\(\rightarrow\) MA=\(\frac{4,8}{0,2}\) =24 \(\rightarrow\)MG
Theo pt nHCL=\(\frac{1}{2}\)NH2 = 0,1(mol) \(\rightarrow\) CMHCl =\(\frac{0,1}{4,48}\) =5/224