Ta có x( y - 3) = 2
Mà x, y \(\in\) Z ; 2\(\in Z\); 2,x > 0
=> y-3 > 0
=> y > 3 > 0
=> x( y - 3) =2 = 1.2 = 2.1
TH1 x ( y - 3 ) = 1.2
Khi đó \(\left\{{}\begin{matrix}x=1\\y-3=2\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}x=1\\y=5\end{matrix}\right.\) ( tm x, y \(\in Z;x,y>0\))
TH2: x (y - 3 ) = 2.1
Khi đó \(\left\{{}\begin{matrix}x=2\\y-3=1\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}x=2\\y=4\end{matrix}\right.\) ( tm x,y \(\in Z;x,y>0\))
Vậy \(\left\{{}\begin{matrix}x=1\\y=5\end{matrix}\right.\) hoặc \(\left\{{}\begin{matrix}x=2\\y=4\end{matrix}\right.\)
Ko biết có đúng ko nx
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