Question

ai giúp em giải bài tìm x này nhé a, [36-x]:18=12 b, [6x - 39]:3=201

giúp e với

Answer 1

a. \(\frac{36-x}{18}=12\)

\(\Leftrightarrow36-x=216\)

\(\Leftrightarrow x=36-216=-180\)

Vậy x=-180

Answer 2

b.\(\frac{6x-39}{3}=201\)

\(\Leftrightarrow6x-39=603\)

\(\Leftrightarrow6x=603+39=642\)

\(\Leftrightarrow x=\frac{642}{6}=107\)

Vậy x=107

Answer 3

a, [36-x]:18=12 b, [6x -39]:3 = 201

36-x = 12.18 6x - 39 = 201.3

36-x = 216 6x - 39 = 603

x = 36-216 6x = 603 + 39

x = -180 6x = 642

x = 642:6

x = 107

Answer 4

a, [36-x]:18=12

36-x = 12.18

36-x = 216

x = 36-216

x = -180

b, [6x -39]:3 = 201

6x - 39 = 201.3

6x - 39 = 603

6x = 603 + 39

6x = 642

x = 642:6

x = 107