\(x^2=x\)
\(\Rightarrow x^2-x=0\)
\(\Rightarrow x.\left(x-1\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=0\\x-1=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=0\\x=0+1\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=0\\x=1\end{matrix}\right.\)
Vậy \(x\in\left\{0;1\right\}.\)
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