\(\frac{-2}{3}.x=\left(\frac{-1}{3}\right)^2\)
\(\frac{-2}{3}.x=\frac{1}{9}\)
\(x=\frac{1}{9}.\frac{-3}{2}\)
\(x=\frac{-1}{6}\)
-\(\frac{2}{3}\).x=(-\(\frac{1}{3}\))\(^2\)
\(\Leftrightarrow\)-\(\frac{2}{3}\).x=\(\frac{1}{9}\)\(\Leftrightarrow\)x=\(\frac{1}{9}\):(\(-\frac{2}{3}\))\(\Leftrightarrow\)x=\(-\frac{1}{6}\)
\(-\frac{2}{3}.x=\left(-\frac{1}{3}\right)^2\)
\(\Rightarrow-\frac{2}{3}.x=\frac{1}{9}\)
\(\Rightarrow x=\frac{1}{9}:\left(-\frac{2}{3}\right)\)
\(\Rightarrow x=-\frac{1}{6}\)
Vậy \(x=-\frac{1}{6}.\)
Chúc bạn học tốt!
