\( {\left( {x + 1} \right)^3} = 64\\ x + 1 = 4\\ x = 4 - 1\\ x = 3 \)
(x + 1)3 = 64
=> (x + 1)3 = 43
=> x + 1 = 4
=> x = 4 - 1 = 3
Vậy x = 3
( x + 1 )3 = 64
=> (x+1)3 = 43
=> x + 1 = 4
=> x = 4 - 1
=> x = 3
Vạy x = 3
(x+1)^3=64
(x+1)^3=4^3
==>x -1 =3
x = 3+1
x = 4
(x + 1)^3=64
(x+1)^3= 4^3
x + 1= 4
=>x=4-1
x=3
cho mk sửa lại
\(\left(x+1\right)^3=64\\ \Leftrightarrow\left(x+1\right)^3=4^3\\ \Leftrightarrow x+1=4\\ \Rightarrow x=3\)
(x + 1)³ = 64
<=> (x + 1)³ = 4^3
<=> x + 1 = 4
<=> x = 4-1
<=> x = 3
Vậy x = 3