Question

Tìm giá trị nhỏ nhất ( Amin ) của :

a) A = 2.|x - 2|+ 16

Answer 1

https://i.imgur.com/CSEpNyl.jpg

Answer 2

Vì |x - 2| ≥ 0 ∀ x ∈ Q

⇒ 2.|x - 2| ≥ 2.0 ∀ x ∈ Q

⇒ 2.|x - 2| + 16 ≥ 2.0+ 16 ∀ x ∈ Q

⇒ A ≥ 16 ∀ x ∈ Q

Dấu bằng xảy ra khi |x - 2|= 0

⇒ x - 2 = 0

⇒ x = 2

Vậy min A = 16 khi x = 2.

Answer 3

\(A=2.\left|x-2\right|+16\)

Ta có: \(\left|x-2\right|\ge0\) \(\forall x.\)

\(\Rightarrow2.\left|x-2\right|+16\ge16\)

Dấu '' = '' xảy ra khi:

\(x-2=0\)

\(\Rightarrow x=0+2\)

\(\Rightarrow x=2.\)

Vậy \(MIN_A=16\) khi \(x=2.\)

Chúc bạn học tốt!

Answer 4

$A=2.\left|x-2\right|+16$

Ta có: $\left|x-2\right|\ge 0$ $\forall x.$

$\Rightarrow 2.\left|x-2\right|+16\ge 16$

Dấu '' = '' xảy ra khi:

$\mathrm{\backslash (\; x-2=0\; \backslash )}$

$\backslash (\; \Rightarrow x=0+2\; \backslash )$

$\backslash (\; \Rightarrow x=2\backslash )$

Vậy $MI{N}_A=16$ khi $\mathrm{\backslash (x\; =\; 2\; \backslash )\; .}$

Answer 5

Cíuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu.........