-X+HCL
\(2Al+6HCl\rightarrow2AlCl_3+3H_2\uparrow\)
x.................................x............\(\frac{3}{2}x\)
\(Fe+2HCl\rightarrow FeCl_2+H_2\uparrow\)
y..............................y..........y
\(Mg+2HCl\rightarrow MgCl_2+H_2\uparrow\)
z................................z............z
Khí : H2 ; dung dịch A :AlCl3, FeCl2 , MgCl2
-A+NaOH
\(AlCl_3+3NaOH\rightarrow Al\left(OH\right)_3\downarrow+3NaCl\)
x.....................................x............................
\(Al\left(OH\right)_3+NaOH\rightarrow NaAlO_2+2H_2O\)
x..............................................x..................
\(FeCl_2+2NaOH\rightarrow Fe\left(OH\right)_2\downarrow+2NaCl\)
y.......................................y............................
\(MgCl_2+2NaOH\rightarrow Mg\left(OH\right)_2\downarrow+2NaCl\)
z..........................................z.............................
\(4Fe\left(OH\right)_2+O_2+2H_2O\rightarrow4Fe\left(OH\right)_3\)
x.....................................................x.........
\(2Fe\left(OH\right)_3-^{t^o}\rightarrow Fe_2O_3+3H_2O\)
x.................................\(\frac{1}{2}x\)...............
\(Mg\left(OH\right)_2-^{t^o}\rightarrow MgO+H_2O\)
z..................................z.................
Gọi x,y,z là số mol của Al, Fe, Mg
Ta có hệ : \(\left\{{}\begin{matrix}27x+56y+24z=24,94\\\frac{3}{2}x+y+z=\frac{19,264}{22,4}=0,86\\\frac{1}{2}.160y+40z=23,2\end{matrix}\right.\)
Giải hệ : \(\left\{{}\begin{matrix}x=0,34\\y=0,23\\z=0,12\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}m_{Al}=0,34.27=9,18\left(g\right)\\m_{Fe}=0,23.56=12,88\left(g\right)\\m_{Mg}=0,12.24=2,88\left(g\right)\end{matrix}\right.\)
Al+3HCl->AlCl3+3/2H2
Fe+2HCl->FeCl2+H2
Mg+2HCl->MgCl2+H2
Gọi số mol của Al,Fe,Mg ll là x,y,z
AlCl3+3NaOH->Al(OH)3
FeCl2+2NaOH->Fe(OH)2+2NaCl
MgCl2+2NaOH->Mg(OH)2+2NaCl
2Al(OH)3->Al2O3+3H2OFe(OH)2->FeO+H2O
Mg(OH)2->MgO+H2O
hệ ptr:27x+56y+24Z=24,94
3/2x+y+z=0,86
51x+72y+40z=23,2Còn lại tự giải nhé
PTHH:2Al+6HCl->2AlCl3+3H2
.............x..............................3/2x
Fe+2HCl->FeCl2+H2
y.....................y.........y
Mg+2HCl->MgCl2+H2
z.......................z.........z
Gọi số mol của Al,Fe,Mg là x,y,z(mol)
PTHH:AlCl3+3NaOH->Al(OH)3
FeCl2+2NaOH->Fe(OH)2+2NaCl
MgCl2+2NaOH->Mg(OH)2+2NaCl
2Al(OH)3->Al2O3+3H2O
Fe(OH)2->FeO+H2O
Mg(OH)2->MgO+H2O
Có:27x+56y+24z=24,94
3/2x+y+z=0,86
51x+72y+40z=23,2
=>x=0,34;y=0,23;z=0,12
=>....
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