Câu hỏi của Lê Việt

Question

1. Phân tích đa thức sau thành nhân tử:

a. x2 - 10x + 16

b. (x + 1)4 + 4 . (x + 1)2

c. x2 . (x - 1) + 16 . ( 1 - x )

Mo Nguyễn Văn · Accepted Answer

a) $x^2-10x+16$

$=\left(x^2-2x\right)-\left(8x-16\right)$

$=x\left(x-2\right)+8\left(x-2\right)$

$=\left(x+8\right)\left(x-2\right)$

b) $\left(x+1\right)^4+4\left(x+1\right)^2$

$=\left(x+1\right)^2\left[\left(x+1\right)^2+4\right]$

$=\left(x+1\right)^2\left(x^2+2x+5\right)$

c)$x^2\left(x-1\right)+16\left(1-x\right)$

$=x^2\left(x-1\right)-16\left(x-1\right)$

$=\left(x^2-16\right)\left(x-1\right)$

$=\left(x-1\right)\left(x+4\right)\left(x-4\right)$

Nhớ tickCâu trả lời: a) $x^2-10x+16$

$=\left(x^2-2x\right)-\left(8x-16\right)$

$=x\left(x-2\right)+8\left(x-2\right)$

$=\left(x+8\right)\left(x-2\right)$

b) $\left(x+1\right)^4+4\left(x+1\right)^2$

$=\left(x+1\right)^2\left[\left(x+1\right)^2+4\right]$

$=\left(x+1\right)^2\left(x^2+2x+5\right)$

c)$x^2\left(x-1\right)+16\left(1-x\right)$

$=x^2\left(x-1\right)-16\left(x-1\right)$

$=\left(x^2-16\right)\left(x-1\right)$

$=\left(x-1\right)\left(x+4\right)\left(x-4\right)$

Nhớ tick

Nhu Phung · Answer

ta có:

a) x^2 -10x +16

= x^2 - 2.x.5 + 25 -9

= (x-5)^2 -3^2

= (x-8)(x-2)

b) (x+1)^4 + 4(x+1)^2

= (x+1)^2(x^2 +2x+5)

c) x^2(x-1) +16(1-x)

= x^2(x-1) -16(x-1)

= (x-1)( x-4)(x+4)Câu trả lời: ta có: