Question

cân bằng phản ứng oxi hóa - khử

Fe_xO_y + HNO₃ -----> \(Fe\left(NO_3\right)_3\) +NO₂+H₂O

Answer 1

3\(Fe_xO_Y+\left(12-2y\right)HNO_3-->\)3xFe(NO₃₎₃ +(3-2y)NO₂ +(6x-y)H₂O

Nhớ tích cho mk nhé

Answer 2

\(PTHH:Fe_xO_y+\left(6x-2y\right)HNO_3\rightarrow xFe\left(NO_3\right)_3+\left(3x-2y\right)NO_2+\left(3x-y\right)H_2O\)

Answer 3

FexOy+(6x-2y)HNO3---> xFe(NO3)3 +(3x-2y)NO2+(3x-y)H2O

Answer 4

a. FexOy + (6x-2y) HNO3 = x Fe(NO3)3 + (3x-2y) NO2+(3x-y) H2O

b. MxOy + 2yHCl ---> xMCl 2y/x + yH2O

c. 2yHCl + FexOy → (3x-2y)FeCl2 + yH2O + (2y-2x)FeCl3