Question

\(\frac{1}{2}^{2x-1}\) = \(\frac{1}{8}\)

Giúp mình vs :))

Answer 1

\(\left(\frac{1}{2}\right)^{2x-1}=\frac{1}{8}\)

=> \(\left(\frac{1}{2}\right)^{2x-1}=\left(\frac{1}{2}\right)^3\)

=> \(2x-1=3\)

=> \(2x=3+1\)

=> \(2x=4\)

=> \(x=4:2\)

=> \(x=2\)

Vậy \(x=2.\)

Chúc bạn học tốt!

Answer 2

Đề này mới đúng chứ ?

\(\left(\frac{1}{2}\right)^{2x-1}=\frac{1}{8}\)

\(\Leftrightarrow\left(\frac{1}{2}\right)^{2x-1}=\left(\frac{1}{2}\right)^3\)

\(\Leftrightarrow2x-1=3\)

<=> 2x=4

<=>x=2

Answer 3

*Bài làm:

~Ta có: \(\left(\frac{1}{2}\right)^{2x-1}\) = \(\frac{1}{8}\)

⇒ \(\left(\frac{1}{2}\right)^{2x}\) : \(\left(\frac{1}{2}\right)^1\) = \(\frac{1}{8}\)

⇒ \(\left(\frac{1^2}{2^2}\right)^x\) : \(\frac{1}{2}\) = \(\frac{1}{8}\)

⇒ \(\left(\frac{1}{4}\right)^x\) = \(\frac{1}{8}\) . \(\frac{1}{2}\)

⇒ \(\left(\frac{1}{4}\right)^x\) = \(\frac{1}{16}\)

⇒ \(\left(\frac{1}{4}\right)^x\) = \(\left(\frac{1}{4}\right)^2\)

⇒ \(x\) = \(2\) .

~Vậy: \(x\) = \(2\) .

➤ Chúc bạn học tốt!