Question

Phân tích đa thức thành nhân tử:

x²(1-x²)-4-4x²

Answer 1

Sửa đề:

\(x^2\left(1-x^2\right)-4+4x^2\)

\(=x^2\left(1-x^2\right)-4\left(1-x^2\right)\)

\(=\left(1-x^2\right)\left(x^2-4\right)\)

\(\left(1-x\right)\left(1+x\right)\left(x-2\right)\left(x+2\right)\)

Answer 2

ko sửa

Answer 3

\(x^2\left(1-x^2\right)-4-4x^2\)

\(=x^2-x^4-4-4x^2\)

\(=-x^4-x^3-2x^2+x^3+x^2+2x-2x^2-2x-4\)

\(=-x^2\left(x^2+x+2\right)+x\left(x^2+x+2\right)-2\left(x^2+x+2\right)\)

\(=\left(x^2+x+2\right)\left(-x^2+x-2\right)\)