Đề bài lạ quá @@
\( \sqrt {2 + 3} + \sqrt {x + 1} = 5\left( {x \ge - 1} \right)\\ \Leftrightarrow \sqrt 5 + \sqrt {x + 1} = 5\\ \Leftrightarrow \sqrt {x + 1} = 5 - \sqrt 5 \\ \Leftrightarrow x + 1 = 25 - 10\sqrt 5 + 5\\ \Leftrightarrow x = 30 - 10\sqrt 5 - 1\\ \Leftrightarrow x = 29 - 10\sqrt 5 \text{(thỏa mãn}) \)
√2+3+√x+1=5(x≥−1)⇔√5+√x+1=5⇔√x+1=5−√5⇔x+1=25−10√5+5⇔x=30−10√5−1⇔x=29−10√5(thỏa mãn)