Ct: Fe\(_x\)S\(_y\)O\(_z\)
%Fe= \(\frac{56x}{400}\) . 100= 28
\(\Leftrightarrow\) x=2
% S= \(\frac{32y}{400}\) . 100= 24
\(\Leftrightarrow\) y= 3
% O= \(\frac{16z}{400}\) . 100= 48
\(\Leftrightarrow\) z= 12
Ct: Fe\(_2\)S\(_3\)O\(_{12}\) \(\Leftrightarrow\) Fe\(_2\)(SO\(_4\))\(_3\)
Gọi: CTHH là : FexSyOz
x : y : z = 28/56 : 24/32 : 48/16 = 2 : 3 : 12
Vậy: CTHH là : Fe2S3O12 hay Fe2(SO4)3
M = 400
<=> 400n = 400
<=> n = 1
Vậy: CTHH là : Fe2(SO4)3