Giải:
Do Ot nằm giữa hai tia Ox, Oy ( giả thiết) \(\Rightarrow\widehat{xOt}+\widehat{tOy}=\widehat{xOy}\)
\(\Leftrightarrow2.\left(\widehat{xOt}+\widehat{tOy}\right)=2.\widehat{xOy}=2.150=300^o\)
\(\Leftrightarrow2.\widehat{xOt}+2.\widehat{tOy}=300^o\)
Lại có: \(\widehat{xOt}=\frac{2}{3}\widehat{tOy}\)
\(\Rightarrow2.\widehat{xOt}=3.\widehat{tOy}\)
Thay 2.\(\widehat{xOt}=3.\widehat{tOy}\), ta có: \(3.\widehat{tOy}+2.\widehat{tOy}=300^o\)
\(\Leftrightarrow\widehat{tOy}=300:\left(3+2\right)=60^o\)
\(\Rightarrow\widehat{xOt}=150^o-60^o=90^o\)
Vậy: góc tOy=60 độ
góc xOt=90 độ.