nC3H5(OH)3= 1.84/92=0.02 mol
(RCOO)3C3H5 + 3NaOH --> C3H5(OH)3 + 3RCOONa
_______________0.06________0.02
mNaOH= 0.06*40=2.4g
Áp dụng ĐLBTKL:
mCb + mNaOH = mglixerol + m muối
m + 2.4= 1.84+18.36
=> m = 17.8g
nC3H5(OH)3= 1.84/0.02 mol
(RCOO)3C3H5 + 3NaOH --> C3H5(OH)2 + 3RCOONa
_______________0.06________0.02
mNaOH= 0.06*40=2.4g
Áp dụng ĐLBTKL:
mCb + mNaOH = mglixerol + m muối
m + 2.4= 1.84+18.36
=> m = 17.8g
nC3H5(OH)3= 1.84/92=0.02 mol
(RCOO)3C3H5 + 3NaOH --> C3H5(OH)2 + 3RCOONa
_______________0.06________0.02
mNaOH= 0.06*40=2.4g
Áp dụng ĐLBTKL:
mCb + mNaOH = mglixerol + m muối
m + 2.4= 1.84+18.36
=> m = 17.8g