2/3+2/4-1/24
=8/12+6/12-1/24
=24/12-1/24
=48/24-1/24
=47/24
Ta có : \(\frac{2}{3}\)+\(\frac{3}{4}\)-\(\frac{1}{24}\)
<=> \(\frac{16}{24}\)+\(\frac{18}{24}\)-\(\frac{1}{24}\)
<=> \(\frac{16+18-1}{24}\)
<=> \(\frac{33}{24}\)
2/3+2/4-1/24
=8/12+6/12-1/24
=24/12-1/24
=48/24-1/24
=47/24
Ta có : \(\frac{2}{3}\)+\(\frac{3}{4}\)-\(\frac{1}{24}\)
<=> \(\frac{16}{24}\)+\(\frac{18}{24}\)-\(\frac{1}{24}\)
<=> \(\frac{16+18-1}{24}\)
<=> \(\frac{33}{24}\)
giải nhanh giúp mình với ạ 1) TÍNH: a) -9/34: 17/4 ; b) 1/1/2(hỗn số) . 1/24 ; c) -5/2: 3/4 ; d) 4/1/5 : (-2/4/5) 2) TÍNH: a) 3/5 + (-4/3) + ( -3/4) ; b) -7/2 + ( -2/3) + (-3/5); c) 3/4 - [(-5/3) - (1/12 + 2/9)] 3) TÌM x : a) 11/12 - (2/5+x) = 2/3 4) a) ( -3/4 + 2/5 ) : 3/7 + ( 3/5 + -1/4 ) : 3/7 b) 7/8 : ( 2/9 - 1/18 ) + 7/8 : ( 1/36 - 5/12 )
Tìm x
a, 580 :( x -24 ) =329 -150 : 2
b, 7 (x-1 ) +35= 25 + 279 :9
c,4 ( 2x+ 7 ) -3 (3x -2 ) =24
d,( x-1 ) (x-2) =3(x-1)
e,( x+ 3 ) + ( x+7 ) + ( x + 11 ) + ........+ ( x+ 79 ) =860
1) 3/4+(-1/8)
2) -5/12+(-7/24)
3)1+(-7/8)
4)13/30-1/3
5)4/21-(-5/28)
Bài 1: Tính
\(\frac{3}{8}.19\frac{1}{3}-\frac{3}{8}.33\frac{1}{3}\)
\(1\frac{4}{23}+\frac{5}{21}-\frac{4}{23}+0,5+\frac{16}{21}\)
\(\frac{21}{47}+\frac{9}{45}+\frac{26}{47}+\frac{4}{5}\)
\(\frac{15}{12}+\frac{5}{13}-\frac{3}{12}-\frac{18}{13}\)
\(\frac{11}{24}-\frac{5}{41}+\frac{13}{24}+0,5-\frac{36}{41}\)
\(\left(-\frac{3}{4}+\frac{2}{3}\right):\frac{5}{11}+\left(-\frac{1}{4}+\frac{1}{3}\right):\frac{5}{11}\)
\(\left(-3\right)^2.\left(\frac{3}{4}-0,25\right)-\left(3\frac{1}{2}-1\frac{1}{2}\right)\)
a) 2\(\dfrac{2}{7}\)x - \(\dfrac{5}{8}\)=\(\dfrac{17}{24}\)
b) -1 - \(\dfrac{1}{2}\) - \(\dfrac{1}{4}\) - \(\dfrac{1}{8}\) . . . \(\dfrac{1}{1024}\)
c) \(1\dfrac{1}{24}\). \(3\dfrac{3}{8}\) : \(3\dfrac{3}{4}\)
Tìm x :
3 + 2^x-1 = 24 - [ 4^2 - ( 2^2 - 1 ) ]
#giúp_với nạ
Tính giá trị biểu thức:
a,\(A=\dfrac{3^6.45^4-15^{13}.5^{-9}}{27^4.25^3+45^6}\)
b,\(^{B=\dfrac{\left[\left(6,2:0,31-\dfrac{5}{6}.0,9\right).0,2+0,15\right]:12}{\left(2+1\dfrac{4}{11}.0,22:0,1\right).\dfrac{1}{33}}}\)
c,\(C=\dfrac{\left(\dfrac{3}{4}\right)^3+\left(\dfrac{5}{4}\right)^3-5\left(\dfrac{4}{3}-\dfrac{5}{4}\right)}{\left(\dfrac{-5}{8}\right)^2+\left(\dfrac{2}{3}\right)^2-\dfrac{5}{6}}\)
d,\(D=\left[\dfrac{\dfrac{17}{24}.9\dfrac{1}{2}-3\dfrac{1}{4}.\dfrac{17}{24}}{3\dfrac{1}{2}.2\dfrac{13}{36}+2\dfrac{13}{36}.2\dfrac{3}{4}}-\dfrac{1}{5}\right]^{-2}\)
Giúp em với chị @Nhã Doanh ới!!!!!!!!
Mai em phải đi thi rồi :((
Tìm x biết: \(3+2^{x-1}=24-\left[4^2-\left(2^2-1\right)\right]\)
Tìm x
a) 2x+3/24 = 3x-1/32
b) x+1/x-2 = 5/6
c) -(x+1)/25 = -4/x+1
d) (5-x).2/25 = -2/x-5
e) x+1/x+4 = x-3/x-2