Hirocacbon A: CxHy
nO2 = V/22.4 = 5.824/22.4 = 0.26 (mol)
mO2 = n.M = 0.26 x 32 = 8.32 (g)
nH2O = m/M = 3.6/18 = 0.2 (mol)
nO2/nH2O = 0.26/0.2 = 13/10
CxHy + (x+y/4) O2 => xCO2 + y/2H2O
Ta có: (x+y/4)/(y/2) = 13/10
=> 10x + 10y/4 = 13y/2
=> x/y = 4/10. CT: C4H10