\(\frac{x+2}{5}=\frac{2-3x}{3}\)
\(\Leftrightarrow3\left(x+2\right)=5\left(2-3x\right)\)
\(\Leftrightarrow3x+6-10+15x=0\)
\(\Leftrightarrow18x=4\)
\(\Leftrightarrow x=\frac{4}{18}=\frac{2}{9}\)
Vậy \(S=\left\{\frac{2}{9}\right\}\)
1/ Cho tỉ lệ thức \(\frac{x}{2}\)=\(\frac{y}{5}\). Biết rằng xy=90. Tìm x và y
2/ Cho tỉ lệ thức \(\frac{3x-y}{x+y}\)= \(\frac{3}{4}\). Tìm \(\frac{x}{y}\)
tìm x biết
a.x:15=8:24
b.36:x=54:3
c.\(3^1_2:0,4=x:1^1_7\)
d.\(\frac{1}{5}x:3=\frac{2}{3}:0,25\)
e.\(\frac{3x+2}{5x+7}=\frac{3x-1}{5x+1}\)
f.\(\frac{x+1}{2x+1}=\frac{0,5x+2}{x+3}\)
Bài 1: Tìm x biết:
a, \(x.\cdot\left(\frac{1}{4}+\frac{1}{5}\right)-\left(\frac{1}{7}+\frac{1}{8}\right)=0\)
b, \(\left(5x-1\right).\left(2x-\frac{1}{3}\right)=0\)
c, \(\frac{3x+2}{5x+7}=\frac{3x-1}{5x+1}\)
d, \(\frac{x+1}{2x+1}=\frac{0,5x+2}{x+3}\)
e, \(\frac{-3}{4}-\left|\frac{4}{5}-x\right|=-1\)
tìm x, y \(\in\) Z biết
1, \(\frac{3x}{4}=\frac{2y}{3}=\frac{9z}{7}\)và x+2y-3z=18
2, \(\frac{x}{2}=\frac{y}{5}=\frac{z}{6}\)và 2x3-3x2+xyz = -108
Tìm \(x,\) biết:
a) \(4\left|3x-1\right|+\left|x\right|-2\left|x-5\right|+7\left|x-3\right|=12\)
b) \(3\left|x+4\right|-\left|2x+1\right|-5\left|x+3\right|+\left|x+9\right|=5\)
c) \( \left|2\frac{1}{5}-x\right|+\left|x-\frac{1}{5}\right|+8\frac{1}{5}=1,2\)
d) \(2\left|x+3\frac{1}{2}\right|+\left|x\right|-3\frac{1}{2}=\left|2\frac{1}{5}-x\right|\)
tìm x, y, z biết
e) 2x=3y; 7z = 5y và 3x-7y+5z=30
f)\(\frac{x}{4}=\frac{y}{5}\)và xy=80
g)\(\frac{x+3}{5}=\frac{y-2}{3}=\frac{z-1}{7}\)và 3x+5y-7z=32
h)\(\frac{x}{4}=\frac{y}{3}\)và x2-y2=63
\(\frac{3}{2}x\)---\(\frac{2}{5}\)= \(\frac{1}{3}\)x\(\frac{1}{3}x\) --- \(\frac{1}{4}\)
2/ 2x --\(\frac{1}{4}\)= \(\frac{5}{6}\)--- \(\frac{1}{2}x\)
3/ \(-\frac{5}{6}\)+ 3x = \(\frac{2}{3}\)--- \(\frac{1}{2}x\)
4/ \(\frac{5}{3}\)[ 3x --- 3 ] + \(\frac{1}{2}\)= \(\frac{1}{2}\)[ 2x ---- 1 ]
1, tìm x từ tỉ lệ thức sau
a, \(\frac{3x+2}{5x+7}\)=\(\frac{3x-1}{5x-1}\)
b, \(\frac{37-x}{x+13}\)=\(\frac{3}{7}\)
c, \(\frac{x+1}{2x+1}\)=\(\frac{0,5.x+2}{x+3}\)
d, \(\frac{x-2}{x+2}\)=\(\frac{x+3}{x-4}\)
f,\(\frac{3x-5}{x}\)=\(\frac{9x}{3x+2}\)
e,\(\frac{x+2}{6}\)=\(\frac{5x-1}{5}\)
tìm x biết
a.\(\frac{-3}{4}-\left|\frac{4}{5}-x\right|=-1\)
b.\(\left|\frac{-1}{2}-x\right|=\frac{1}{3}\)
c.\(\left|2^1_2+x\right|-\frac{-2}{3}=3\)
d.\(\frac{-5}{7}-\left|\frac{1}{2}-x\right|=\frac{-11}{4}\)
e.\(\left|3x+4\right|=2\left|2x-9\right|\)
