\(a,\Delta'=b'^2-ac\\ =\left(-1\right)^2-1.\left(3m-4\right)\\ =1-3m+4\\ =5-3m\)
Để phương trình có 2 nghiệm \(x_1,x_2\) thì: \(\Delta'>0\Rightarrow5-3m>0\Rightarrow m< \frac{5}{3}\)
b/ \(\left\{{}\begin{matrix}x_1+x_2=2\\x_1x_2=3m-4\end{matrix}\right.\)
\(x_1^2x_2+x_1x_2^2=1\)
\(\Leftrightarrow x_1x_2\left(x_1+x_2\right)-1=0\)
\(\Leftrightarrow2\left(3m-4\right)-1=0\)
\(\Rightarrow m=\frac{3}{2}\)