\(7⋮x-4\)
\(\Rightarrow x-4\inƯ\left(7\right)=\left\{\pm1;\pm7\right\}\)
Xét bảng :
x-4 | 1 | -1 | 7 | -7 |
x | 5 | 3 | 11 | -3 |
Vậy....
Ta có: 7 \(⋮\) x-4
\(\Rightarrow x-4\inƯ\left(7\right)=\left\{1;-1;7;-7\right\}\)
\(\Rightarrow x\in\left\{5;3;11;-3\right\}\)
Vậy: \(x\in\left\{5;3;11;-3\right\}\)