Bài 4: Phương trình tích
Các câu hỏi tương tự
Bài 8: Giải các phương trình tích sau:
4. a) 3x2 + 2x – 1 0 b) x2 – 5x + 6 0
c) x2 – 3x + 2 0 d) 2x2 – 6x + 1 0
e) 4x2 – 12x + 5 0 f) 2x2 + 5x + 3 0
g) x2 + x – 2 0 h) x2 – 4x + 3 0
i) 2x2 + 5x – 3 0 j) x2 + 6x – 16 0
5. a) 3x2 + 12x – 66 0 b) 9x2 – 30x + 225 0
c) x2 + 3x – 10 0 d) 3x2 – 7x + 1 0
e) 3x2 –...
Đọc tiếp
Bài 8: Giải các phương trình tích sau:
4. a) 3x2 + 2x – 1 = 0 b) x2 – 5x + 6 = 0
c) x2 – 3x + 2 = 0 d) 2x2 – 6x + 1 = 0
e) 4x2 – 12x + 5 = 0 f) 2x2 + 5x + 3 = 0
g) x2 + x – 2 = 0 h) x2 – 4x + 3 = 0
i) 2x2 + 5x – 3 = 0 j) x2 + 6x – 16 = 0
5. a) 3x2 + 12x – 66 = 0 b) 9x2 – 30x + 225 = 0
c) x2 + 3x – 10 = 0 d) 3x2 – 7x + 1 = 0
e) 3x2 – 7x + 8 = 0 f) 4x2 – 12x + 9 = 0
g) 3x2 + 7x + 2 = 0 h) x2 – 4x + 1 = 0
i) 2x2 – 6x + 1 = 0 j) 3x2 + 4x – 4 = 0
Bài 5: Giải phương trình
a) x ( x+1) ( x – 1) ( x+2) =24
b) ( x – 4) ( x – 5) ( x – 6) ( x – 7) = 1680
c) 2x ( 8x – 1) 2 ( 4x – 1) = 9
d) ( 2x + 1)( x + 1) 2 ( 2x + 3) = 18
e) (x 2 – 6x +9 ) 2 – 15( x 2 – 6x +10) = 1
f) ( x 2 + 1) 2 + 3x ( x 2 + 1) + 2x 2 = 0
g) ( x 2 – 9) 2 = 12x + 1
Bài 6: Giải phương trình
a) ( x + 3) 4 + ( x+ 5 ) 4 = 16
b) ( x – 2) 4 + ( x – 3) 4 = 1
Bài 5: Giải phương trình
a) x ( x+1) ( x – 1) ( x+2) =24
b) ( x – 4) ( x – 5) ( x – 6) ( x – 7) = 1680
c) 2x ( 8x – 1) 2 ( 4x – 1) = 9
d) ( 2x + 1)( x + 1) 2 ( 2x + 3) = 18
e) (x 2 – 6x +9 ) 2 – 15( x 2 – 6x +10) = 1
f) ( x 2 + 1) 2 + 3x ( x 2 + 1) + 2x 2 = 0
g) ( x 2 – 9) 2 = 12x + 1
Bài 6: Giải phương trình
a) ( x + 3) 4 + ( x+ 5 ) 4 = 16
b) ( x – 2) 4 + ( x – 3) 4 = 1
Bài 1: Giải các phương trình tích sau:
2. a) (3x + 2)(x2 –1) (9x2 – 4)(x + 1) b)x(x + 3)(x – 3) – (x + 2)(x2 – 2x + 4) 0
c) 2x(x – 3) + 5(x – 3) 0 d) (3x – 1)(x2 + 2) (3x – 1)(7x – 10)
e) (x + 2)(3 – 4x) x2 + 4x + 4 f) x(2x – 7) – 4x + 14 0
g) 3x – 15 2x(x – 5) h) (2x + 1)(3x – 2) (5x – 8)(2x + 1)
i) 0,5x(x – 3) (x – 3)(1,5x – 1) j) (2x2 + 1)(4x – 3) (x – 12)(2x2 + 1)
k) x(2x – 9) 3x(x – 5) l) (x – 1)(5x + 3) (3...
Đọc tiếp
Bài 1: Giải các phương trình tích sau:
2. a) (3x + 2)(x2 –1) = (9x2 – 4)(x + 1) b)x(x + 3)(x – 3) – (x + 2)(x2 – 2x + 4) = 0
c) 2x(x – 3) + 5(x – 3) = 0 d) (3x – 1)(x2 + 2) = (3x – 1)(7x – 10)
e) (x + 2)(3 – 4x) = x2 + 4x + 4 f) x(2x – 7) – 4x + 14 = 0
g) 3x – 15 = 2x(x – 5) h) (2x + 1)(3x – 2) = (5x – 8)(2x + 1)
i) 0,5x(x – 3) = (x – 3)(1,5x – 1) j) (2x2 + 1)(4x – 3) = (x – 12)(2x2 + 1)
k) x(2x – 9) = 3x(x – 5) l) (x – 1)(5x + 3) = (3x – 8)(x – 1)
giải các phương trình
a) (3x-2)(3x-1) = (3x+1)2
b) (4x-1)(x+1) = (2x-3)2
c) (5x+1)2 = (7x-3)(7x+2)
d) (4-3x)(4+3x)=(9x-3)(1-x)
e) x(x+1)(x+2)(x+3)=24
g) (7x - 2)2= (7x-3)(7x+2)
1,Giải PT sau
a, (5x+3)(x2+4)(x-4)=0
b, (4x-1)(x-3)-(x-2)(5x+2)=0
c, (x+3)(x-5)+(x+3)(3x-4)=0
d, (x+6)(3x-1)+x2-36=0
e, 0,75x(x+5)=(x+5)(3-1,25x)
Giải phương trình
a. x (x+1)(x-1)(x+2)=24
b.(x-4)(x-5)(x-6)(x-7)=1680
c. (x+2)(x+3)(x-5)(x-6)=180
d.2x(8x-1)2(4x-1)=9
e. (12x+7)2(3x+2)(2x+1)=3
g. (2x+1)(x+1)2(2x+3)=18
5/ (x2 – 4) + (x – 2)(4 – 2x) = 0
6/ x(2x – 7) – 4x + 14 = 0 7/ x2 – x – (3x – 3) = 0
8/ (x2 – 2x + 1) – 4 = 0 9/ 4x2 + 4x + 1 = x2
10/ x2 – x = - 2x + 2 11/ x2 – 5x + 6 = 0
11/ x^2 -- 5x + 6 = 0
Câu 11 là x mũ 2 nha giúp dùm e nha anh chị .
Giải các phương trình sau:
a/(2x-1)2=49
b/ (2x+7)2=9(x+2)2
c/ 4(2x+7)2-9(x+3)2=0
d/ (5x-3)2-(4x-7)2=0
e/ (x+2)2=9(x2-4x+4)
f/ (5x2-2x+10)2=(3x2+10x-8)2