Question

\(^{x^2+x-6=0}\)

Answer 1

đề là gì v bạn

Answer 2

\(\Leftrightarrow x^2+x=6\)

\(\Leftrightarrow x^2+2.x.\dfrac{1}{2}+\dfrac{1}{4}=6+\dfrac{1}{4}\)

\(\Leftrightarrow\left(x+\dfrac{1}{2}\right)^2=\dfrac{25}{4}\)

\(\Leftrightarrow x+2=\pm\dfrac{5}{2}\)

\(\Leftrightarrow\left[{}\begin{matrix}x+2=\dfrac{5}{2}\\x+2=\dfrac{-5}{2}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{2}\\x=-\dfrac{9}{2}\end{matrix}\right.\)

Vậy nghiệm của pt là : \(x_1=\dfrac{1}{2};x_2=-\dfrac{9}{2}\)