\(\left(x^2+1\right)\left(x-1\right)^2\left(3x-1\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x^2+1=0\\\left(x-1\right)^2=0\\3x-1=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x^2=-1\left(vl\right)\\x=1\\x=\dfrac{1}{3}\end{matrix}\right.\)