CaCO3 \(\underrightarrow{to}\) CaO + CO2
\(m_{CaCO_3}=500\times80\%=400\left(g\right)\)
\(\Rightarrow n_{CaCO_3}=\dfrac{400}{100}=4\left(mol\right)\)
a) theo PT: \(n_{CaO}=n_{CaCO_3}=4\left(mol\right)\)
\(\Rightarrow m_{CaO}=4\times56=224\left(g\right)\)
Theo PT: \(n_{CO_2}=n_{CaCO_3}=4\left(mol\right)\)
\(\Rightarrow m_{CO_2}=4\times44=176\left(g\right)\)
Do \(H=70\%\) \(\Rightarrow m_{CaO}tt=224\times70\%=156,8\left(g\right)\)
\(m_{CO_2}tt=176\times70\%=123,2\left(g\right)\)
\(m_X=500-123,2=376,8\left(g\right)\)
b) \(\%CaO=\dfrac{156,8}{376,8}\times100\%=41,72\%\)