a) 2Al + 6HCl → 2AlCl3 + 3H2
\(n_{Al}=\dfrac{6,75}{27}=0,25\left(mol\right)\)
b) Theo PT: \(n_{H_2}=\dfrac{3}{2}n_{Al}=\dfrac{3}{2}\times0,25=0,375\left(mol\right)\)
\(\Rightarrow V_{H_2}=0,375\times22,4=8,4\left(l\right)\)
c) Theo PT: \(n_{HCl}pư=3n_{Al}=3\times0,25=0,75\left(mol\right)\)
\(\Rightarrow m_{HCl}pư=0,75\times36,5=27,375\left(g\right)\)
d) Theo PT: \(n_{AlCl_3}=n_{Al}=0,25\left(mol\right)\)
\(\Rightarrow m_{AlCl_3}=0,25\times133,5=33,375\left(g\right)\)