\(5\left(x-1\right)+2x\left(1-x\right)=0\\ \Leftrightarrow5\left(x-1\right)-2x\left(x-1\right)=0\\ \Leftrightarrow\left(x-1\right)\left(5-2x\right)=0\Leftrightarrow\left[{}\begin{matrix}x-1=0\\5-2x=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=1\\x=\dfrac{5}{2}\end{matrix}\right.\)
Vậy x = 1 hoặc x = \(\dfrac{5}{2}\)