Question

Cho hàm số y= f(x)= x\(^{^2}\)- 6x + 9

Tính f(3); f(0)

Answer 1

Ta có :

\(f\left(x\right)=x^2-6x+9\)

\(\Leftrightarrow f\left(3\right)=3^2-6.3+9\)

\(\Leftrightarrow f\left(3\right)=0\)

\(\Leftrightarrow f\left(0\right)=0^2-6.0+9\)

\(\Leftrightarrow f\left(0\right)=9\)

Vậy..

Answer 2

ta có :f(x)=x^2-6x+9

=>f(3)=3^2-6.3+9

=>f(3)=9-18+9

=>f(3)=-9+9

=>f(3)=0

cậu làm như thế với f(0) nhé

Answer 3

\(y=f\left(x\right)=x^2-6x+9\)

➩\(f\left(3\right)=3^2-6\cdot3+9=9-18+9=0\)

Vậy : \(f\left(3\right)=0\)

➩\(f\left(0\right)=0^2-6\cdot0+9=0-0+9=9\)

Vậy : \(f\left(0\right)=9\)