\(\dfrac{x}{15}=\dfrac{y}{7}\&x-2y=16\)
\(\dfrac{x}{15}=\dfrac{y}{7}\Rightarrow\dfrac{x}{15}=\dfrac{2y}{14}\)
Áp dụng tính chất dãy tỉ số bằng nhau:
\(\dfrac{x}{15}=\dfrac{2y}{14}=\dfrac{x-2y}{15-14}=\dfrac{16}{1}=16\)
\(\Rightarrow\left\{{}\begin{matrix}\dfrac{x}{15}=16\\\dfrac{y}{7}=16\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=240\\y=112\end{matrix}\right.\)
Vậy,...
\(\dfrac{x}{15}=\dfrac{y}{7}=\dfrac{2y}{14}=\dfrac{x-2y}{15-14}=\dfrac{16}{1}=16\)
\(\Rightarrow\left\{{}\begin{matrix}x=15.16=240\\y=7.16=112\end{matrix}\right.\)
Ta có : \(\dfrac{y}{7}=\dfrac{2y}{14}\)
Mà x - 2y = 16
Theo tính chất dãy tỉ số bằng nhau, ta có :
\(\dfrac{x}{15}=\dfrac{2y}{14}=\dfrac{x-2y}{15-14}=16\)
Do đó : \(\dfrac{x}{15}=16\Rightarrow x=16.5=80\)
\(\dfrac{2y}{14}=16\Rightarrow y=16.14:2=112\)
Vậy x = 8= ; y = 112